x^2+7=(x+1)(x+1)

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Solution for x^2+7=(x+1)(x+1) equation:


Simplifying
x2 + 7 = (x + 1)(x + 1)

Reorder the terms:
7 + x2 = (x + 1)(x + 1)

Reorder the terms:
7 + x2 = (1 + x)(x + 1)

Reorder the terms:
7 + x2 = (1 + x)(1 + x)

Multiply (1 + x) * (1 + x)
7 + x2 = (1(1 + x) + x(1 + x))
7 + x2 = ((1 * 1 + x * 1) + x(1 + x))
7 + x2 = ((1 + 1x) + x(1 + x))
7 + x2 = (1 + 1x + (1 * x + x * x))
7 + x2 = (1 + 1x + (1x + x2))

Combine like terms: 1x + 1x = 2x
7 + x2 = (1 + 2x + x2)

Add '-1x2' to each side of the equation.
7 + x2 + -1x2 = 1 + 2x + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
7 + 0 = 1 + 2x + x2 + -1x2
7 = 1 + 2x + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
7 = 1 + 2x + 0
7 = 1 + 2x

Solving
7 = 1 + 2x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2x' to each side of the equation.
7 + -2x = 1 + 2x + -2x

Combine like terms: 2x + -2x = 0
7 + -2x = 1 + 0
7 + -2x = 1

Add '-7' to each side of the equation.
7 + -7 + -2x = 1 + -7

Combine like terms: 7 + -7 = 0
0 + -2x = 1 + -7
-2x = 1 + -7

Combine like terms: 1 + -7 = -6
-2x = -6

Divide each side by '-2'.
x = 3

Simplifying
x = 3

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